Sequential Auditing on Laplace Mechanism epsilon = 0.1 (mu = 0.1)
0Rejection RateAuditor from [23]
Evaluation Results
| Method | Links | ||
|---|---|---|---|
| Auditor from [23]Mechanism=DPLaplace2026.02 | 0 | — | |
| Algorithm 1 (sequential f-DP auditor)Mechanism=DPLaplace2026.02 | 2.7 | — | |
| Algorithm 1 (sequential f-DP auditor)Mechanism=NonDPLaplace12026.02 | 100 | — | |
| Auditor from [23]Mechanism=NonDPLaplace12026.02 | 100 | 92,061.6 |